Explain me how can possibly exploit the following program:
#include <stdlib.h>
#include <unistd.h>
#include <stdio.h>

int main(int argc, char **argv)
{
int vuln;
char buffer[32];

    vuln = 0;
    gets(buffer);

    if(vuln != 0) {
            printf("WIN\n");
    }else {
    `printf("Try again :(\n");
    }
} Provide your response in exactly 7 paragraphs (separated nearby paragraphs with 3 aterisk symbols ***).
user