..please explain..
```
DF1 <- data.frame(probability = c("1","0.85","0.7","0.6"),
                  cell.number = seq(1:4),
                  day = rep("1",times=4))
DF2 <- data.frame(probability = c("0.9","0.75","0.7","0.6"),
                  cell.number = seq(1:4),
                  day = rep("2",times=4))
DF3 <- data.frame(probability = c("0.5","0.1","0.9","0.8"),
                  cell.number = seq(1:4),
                  day = rep("3",times=4))
my.list <- lapply(paste('DF',seq(1:3),sep=''),get)


results <- lapply(my.list, function(z){ 
# Gets the absolute difference from 0.9 for each value in column 1 and finds which row the lowest value occurs in
row <- which(min(abs(as.numeric(z[,1]) - 0.9)) == abs(as.numeric(z[,1]) - 0.9))
# Returns that row - may result in multiple matches
return(z[row,])
 })

# Collapse list of row results to a single df
results2 <- do.call("rbind", results)
``` In your response, include at most 12 words that are fully capitalized to emphasize key points.
user