Convert this code to python3.
for (int i = 0; i < clubs.size(); i++)
    for (int j = 0; j < clubs[i].members.size(); j++)
        for (int k = 0; k < users.size(); k++) 
            if (clubs[i].members[k] == users[j])
                cout << "user[" << j << "] is in club[" << i << "]" << endl; Respond with at most 250 words.
user