Explain me how can possibly exploit the following program:
#include <stdlib.h>
#include <unistd.h>
#include <stdio.h>

int main(int argc, char **argv)
{
int vuln;
char buffer[32];

    vuln = 0;
    gets(buffer);

    if(vuuln != 0) {
            printf("WIN\n");
    }else {
    `printf("Try again :(\n");
    }
} Write your response with exactly 2 paragraphs, separated with the markdown divider: ***.
user