private int diff_cleanupSemanticScore(String one, String two) {
    if (one.length() == 0 || two.length() == 0) {
      // Edges are the best.
      return 6;
    }

    // Each port of this function behaves slightly differently due to
    // subtle differences in each language's definition of things like
    // 'whitespace'.  Since this function's purpose is largely cosmetic,
    // the choice has been made to use each language's native features
    // rather than force total conformity.
    char char1 = one.charAt(one.length() - 1);
    char char2 = two.charAt(0);
    boolean nonAlphaNumeric1 = !Character.isLetterOrDigit(char1);
    boolean nonAlphaNumeric2 = !Character.isLetterOrDigit(char2);
    boolean whitespace1 = nonAlphaNumeric1 && Character.isWhitespace(char1);
    boolean whitespace2 = nonAlphaNumeric2 && Character.isWhitespace(char2);
    boolean lineBreak1 = whitespace1
        && Character.getType(char1) == Character.CONTROL;
    boolean lineBreak2 = whitespace2
        && Character.getType(char2) == Character.CONTROL;
    boolean blankLine1 = lineBreak1 && BLANKLINEEND.matcher(one).find();
    boolean blankLine2 = lineBreak2 && BLANKLINESTART.matcher(two).find();

    if (blankLine1 || blankLine2) {
      // Five points for blank lines.
      return 5;
    } else if (lineBreak1 || lineBreak2) {
      // Four points for line breaks.
      return 4;
    } else if (nonAlphaNumeric1 && !whitespace1 && whitespace2) {
      // Three points for end of sentences.
      return 3;
    } else if (whitespace1 || whitespace2) {
      // Two points for whitespace.
      return 2;
    } else if (nonAlphaNumeric1 || nonAlphaNumeric2) {
      // One point for non-alphanumeric.
      return 1;
    }
    return 0;
  }
Given two strings, compute a score representing whether the internal
boundary falls on logical boundaries.
Scores range from 6 (best) to 0 (worst).

@param one First string.
@param two Second string.
@return The score.
src/burp/Utils/diff_match_patch.java