public static void main(String args[]){
        NumberOfPairWithXPowerYGreaterThanYPowerX nop = new NumberOfPairWithXPowerYGreaterThanYPowerX();
        int X[] = {7,9,5,8,9,11,0,1,1,3};
        int Y[] = {6,8,9,11,14,5,1,0,2,3,9};
        System.out.println(nop.countPairs(X, Y));
    }
http://www.geeksforgeeks.org/find-number-pairs-xy-yx/
src/com/interview/binarysearch/NumberOfPairWithXPowerYGreaterThanYPowerX.java