text:
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# cannot get on some sites

Hello again !

another day, onother problem as they say :
i can get on the internet, to sites like yahoo, google.
i am using broadband connection, scanned with ravantivirus, housecall, adaware, spybot, hijackthis and removed some troublemakers (not excessive)
In regedit , under hkey_local_machine\system\ControlSet001\services\DHCP\DependonService ,
i found these entries :
Tcpip
Afd
NetBT
SYMTDI
in the event log, i find errors referring to DCOM

help appreciated !
0
nobus
• 63
• 28
• 25
• +2
2 Solutions

Commented:
Hello nobus =)

Have you checked the HOSTS file from C:\Windows\System32\drivers\etc
i mean open it in Notepad and check there if it contains the entries for these websites which you cannot get to access ?
if they have then remove them and save the file, restart and now check if same problem ?
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Commented:
Also im considering that you have already tried deleting the Internet Temp Files and history from IE options :)
So how about creating a new user account and check there for the problem :-?
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Author Commented:
i checked it now, it contained
127.0.0.1
i deleted it, but it gives the same effect

more suggestions ?
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Author Commented:
I deleted the internet temp files, i will delete the history, if it does not work, i'll make another account

Thanks
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Commented:
yeah just tell me about the new account results... so that it can be confirmed that the problem is system-wise or just user-wise :)
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Author Commented:
it works with a new account, what do you suggest to do now, there are 5 accounts here (6 with my test account)
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Commented:
Try this first,

Boot into safemode, and then goto My Computer>Tools>Folder Options>View and turn on the feature of Show Hidden Files
Goto C:\Documents and Settings\your usernmae\Local Settings\Temp and delete all files present here
Goto C:\Documents and Settings\your usernmae\Local Settings\Temporary Internet Files, and delete the folder of ContentIE

Restart back in normal mode to login with the corrupted user, and check for the problem now ??
if same issue then i must say that the corruption is registry-wise, and its better that you transfer to the new account :)

How to copy data from a corrupted user profile to a new profile
http://support.microsoft.com/default.aspx?scid=kb;EN-US;811151
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Author Commented:
I suppose i have to repeat the procedure for every user account?
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Commented:
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Author Commented:
Right !
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Commented:
no actually what i meant was.... you can delete the temp and cookies files from all users only from Administrator. you dont have to login with each user profile to do that method :)
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Author Commented:
did that already, thanks for your concern though (pictures the real master as they say...)
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Commented:
ok we can try one more thing before we are forced to move 6 profiles to the new ones =\
from the new user account opne regedit and then go here,

HKEY_CURRENT_USER\Software\Microsoft\Windows\Current Version\
click the '+' sign and then right click the Internet Settings folder and click Export
save the reg file in a new folder on C: drive
then restart and now login as one of the problematic user
now open regdit and goto HKEY_CURRENT_USER\Software\Microsoft\Windows\Current Version\ again
here delete the Internet Settings folder and now close regedit
now open C:\New Folder and then double click the reg file which you exported from the new user
say yes to merge the information, now logoff and login with the same user
check if same problem still ??
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Author Commented:
I meant, i cleared the temp files, and it works;
there is one site  (a bank) complaining about jave script not being enabled. Maybe you know that too?
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Commented:
>> I meant, i cleared the temp files, and it works;
wow..... then why cant i see a big Smile on you face, something like this :-D
lol... ;-)

>> there is one site  (a bank) complaining about jave script not being enabled. Maybe you know that too?
if you alread checked under Security options that Java is enabled, then try this, goto Start>Run and type these lines hitting enter after each line, then restart you machine and check now if same complaint ??

regsrv32 urlmon.dll
regsrv32 Mshtml.dll
regsrv32 Actxprxy.dll
regsrv32 Oleaut32.dll
regsrv32 Shell32.dll
regsrv32 shdocvw.dll
regsrv32 browseui.dll
regsrv32 msjava.dll
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Author Commented:
:-D
:-D
:-D
i get this answer : could not find the file regsrvr32
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Commented:
>> could not find the file regsrvr32
its "regsrv32" and not "regsrvr32" ;-)
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Author Commented:
Sorry, that was a typo, i copied your command simply in the run box, so please read :

could not find the file regsrv32
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Commented:
what an idiot im.... i had a typo also... its regsvr32... that stupid svr always get changed with srv =\
so here are the "correct" lines =(

regsvr32 urlmon.dll
regsvr32 Mshtml.dll
regsvr32 Actxprxy.dll
regsvr32 Oleaut32.dll
regsvr32 Shell32.dll
regsvr32 shdocvw.dll
regsvr32 browseui.dll
regsvr32 msjava.dll
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Author Commented:
so, if i understand you correctly, my typo was no typo, but yours which was no typo was a typo ??

but i get still the same : could not find ....
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Commented:
you mean when you type, regsvr32 urlmon.dll, you get the error ??
try typing it from command prompt.... same thing ??

if Yes then run this tool and check what it reports ?
http://windowsxp.mvps.org/IEFIX.htm
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Author Commented:
Still no joy on this one
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Commented:
can you load java applets on the other websites ??
like what if you try to load Pool from http://games.yahoo.com ??
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Author Commented:
i do not see anything on the pool page, empty squares with the known cross
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Commented:
then that means java is not working on the system, try reinstalling it!

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Author Commented:
i installed java; the site says : you have to enable javascripts; i did so under the security tab, but i still cannot view the site

any thoughts?
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Commented:
pool works now or not ??
can you give me the link to this site which is not working ?
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Author Commented:
link (works on other computers ok)  www.kbc.be
i have the impression javaVM does not install properly (too quick)
i have an empty page at :

http://leagues.games.yahoo.com/league/strawberry/
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Commented:
lol that page is for league members.... im not among them =\
But i can see the bank site very well.... and i can see also that they are using javascripts!

tell me one thing..... does the new user account(which was working fine with google) has this problem of java also or its also effected ??
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Author Commented:
Yes, it has the same problem
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Commented:
ok tell me, have you tried disabling any firewall temporary to check for the problem..... and is norton installed on the machine ??

Try Downloading and Installing Windows Script 5.6 for Windows 2000 and XP to check if same problem still ??
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Author Commented:
Firewall is disabled
Norton 2003 Pro is installed
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Commented:
>> Norton 2003 Pro is installed
ahhhhh... =\
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Author Commented:
IS THIS SITE CHANGED   ? ? ?
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Commented:
what happened ??
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Commented:
Did no one get this?

<Quote>

i checked it now, it contained
127.0.0.1
i deleted it, but it gives the same effect

</Quote>

ROFLMAO
LOL
To Much! This is twice in one night I've laughed my head off at this site. Man...phew....I broke out in a sweat I'm laughing so hard,

OK-first thing ya gotta do, trust me on this one, and it may not fix everything or even anything but ya got to do it right now: Open the following file in notepad:

c:\windows\ is this windows2k or XP, LOL-I can't even remember which thread I'm in for god's sakes...I am sorry people but this is funny....ok, ok...

this file:

c:\windows\system32\drivers\etc\HOSTS

MAKE SURE THAT THE LINE

127.0.0.1    locahost

IS THERE! IF it isn't there PUT IT THERE....LOL

Cheers All,

Jatcan

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Commented:
This is internet explorer right? Do you have any problems with any other applications on your PC?

sigh:try this:

record your proxy settings (if any):

To check proxy settings, open Internet options from control panel and click connection
, then lan settings button. Write down any config's you may have in here before deleting the below registry
keys.

close all IE windows.

Click start button=>run=>type in regedit=>click OK
Click the file menu=>export registry file=>browse to the root of a drive (C:\ will do nicely)
Type in a file name (regback.reg will do nicely) click save-remember where you save this-just in case

navigate to the following locations:

HKEY_CURRENT_USER\Software\Microsoft\Internet Explorer (1.)
HKEY_CURRENT_USER\Software\Microsoft\Windows\CurrentVersion\Internet Settings (2.)
HKEY_LOCAL_MACHINE\SOFTWARE\Microsoft\Windows\CurrentVersion\Internet Settings (2.)

Delete the following keys located on the left had side of the registry window:

1.) Internet Explorer
*DO NOT delete this one from HKEY_LOCAL_MACHINE or you will need to reinstall IE at best and your OS(WIndows) at worst...*

2.)Internet Settings from both hives (may not exist in HKEY_LOCAL_MACHINE)

This  puts all Internet Explorer Settings back to their defaults...you will have to re-configure you're IE the way you like it on the advanced tab after performing these steps and also re-enter any proxy settings you may have had.

So, if it is a javascript problem and accessing websites there might be a policy or something on IE...who knows, it can't hurt to do this, that way configuration is ruled out and then the troubleshooting on other things starts.

Cheers,

J

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Commented:
oh and before you do any re-configuring go ahead and test the browser on one of those in-accessible websites.

Cheers,

jatcan

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Author Commented:
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Commented:
it is the IP address of your local machine and your machine depends on it for some services, network related services...if you open a cmd prompt and type ping 127.0.0.1 <enter> you should get replies, same thing if you type in ping localhost <enter>

Also, if you are sure you have performed ALL the above sugestions, then maybe it is a routing issue on the ISP side...rare but not unheard of, I had a problem similar to that a few yeasr ago and it took a long time to convince the ISP that it was THEM...

What are the exact URL's to these webpages, lets see if some of us are having any problems with them...then again, they won't check even that out for you unless you do a re-install of the OS...

Cheers,

J

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Author Commented:
jatcan, with other machines you can access the page without problems( it' s a bank)   :   www.kbc.be
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Commented:
yup the page loads just fine for me..ok let sty this then

open up cmd form start button run=>type in "cmd" without the quotes, click OPK
then type in the follwing;

ping www.kbc.be <enter>

you should get four replies...if you don't try typing this in the same window:

ipconfig /flushdns <enter>
then
ping www.kbc.be <enter>

This will rule out routing, if yuo get replies it is not a routing issue...as long as those replies are under say 200ms?

I got to go to bed now, it is 4AM and I have to get up a 9AM and drive top Montreal (2hrs from me) so good night all, see ya sometime after the weekend, wifey is abck from a two week busines trip and we're staying away from the PC's this weekend...

Cheers,

J

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Author Commented:
What is this ?  >>>   click OPK
the reply is 4 x send failed errorcode 65
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Author Commented:
even after flushing the dns cache, error 65
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Commented:
good we have an error code...bnut I DO need some sleep...
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Commented:
Heh, heh make sure your nic is plugged into the Rj45 cable wil ya?
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Commented:
Ping: transmit failed, error code 10050 or 65

Symptom: When attempting to verify network connectivity with a remote computer by using the Ping.exe command, you may receive a command-line error message similar to the following: Ping: transmit failed, error code 65 or PING: transmit failed, error code 10050.

Resolutions: This behavior can occur if the following conditions are true: 1) ICS is enabled; 2) a firewall software is running on the computer; 3) The ZoneLabs program is not correctly configured for ICS.

To fix the problem: 1) re-configure ZoneAlarm for ICS. 2) Remove the Zone Labs firewall software from the computer.
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Commented:

http://support.microsoft.com/?kbid=316414

Good night bud, hope you get this all worked out soon!

Cheers,

Jatcan
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Commented:
It all boils down to a firewall software I beleive, something somewhere is stopping the packets from leaving your PC, doesn't look like theyre even hitting the wire. open up services.msc by clicking start button=>run and tyoping it in:

Locate Internet Connection hsaring=.disable it and set it's startup type to manual (it's a drop down menu)

then find Windows Firewall or firewall or Window Secuiry (whatever they're calling it nowadays) and do the same for it, disable it and set it's starup type to "disbaled" not manual...
reboot and try it all over again with the website.

Cheers,

Jatcan

PS: I REALLY am off to bed now...night...
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Commented:
Did you fix the HOSTS file----that may throw  a muck in your place to go surfing around the net...

Cheers,

J and Good Night.
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Author Commented:
thanks, will try all suggestion
BTW : cable was plugged, i can access many sites, just not some
fixed the hosts file (i kept a copy)
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Author Commented:
There is no zone Alarm installed, Firewall is disabled.
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Author Commented:
i also found out that i cannot make a network connection
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Commented:
You could try rsetting IP:

In Windows XP, a reset command is available in the IP context of the NetShell utility. When you run the reset command, it rewrites pertinent registry keys that are used by the Internet Protocol (TCP/IP) stack to reach the same result as the removal and the reinstallation of the protocol.

http://support.microsoft.com/kb/299357

open CMD, type in the following command inclucing path\to\restlog.txt (the file will be created)

netsh int ip reset c:\resetlog.txt

then try it again....

Cheers J
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Commented:
The only other times I seen this was:

a crossover was used instead of a straight through cable
bad nic -try another network card
ISP maps to mac address, change of network device will not allow access: contact ISP with new mac addrress.

Cheers,

J
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Author Commented:
Hello, good morning i presume ?

i did the reset, but got no change.
I cannot make a network connection, and did try another good card, still no connection, or access to the famous site.

more suggestions? it seems to be a tough one
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Commented:
yeah-I don't have to leave for Mntreal until 11:30Am, plans change, good for me, I need more sleep, just droped on here quickly to see how people were doing today?

You said y9uo CAn surf to other websites or not, I can't remember and cant see it in the above posts?

Jatcan
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Author Commented:
BUT i cannot get on the www.kbc.be site (with this computer, with others it is accessible)
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Commented:
nobus, just a quick comment.....

have you power cycled your router? (very tired now, not thinking clearly, too tired and lazy to describe my idea right now)

Hope you had a Happy Turkey Day

Mugman
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Author Commented:
We do not have turkey days here, just normal working day.
It is the same router i use with the other normally working computers
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Commented:
although it doesn't seem logical, power it on and off anyway. I've seen routers do things simular to this before, I don't know what caused it, it's almost as if the router developed a problem with a specific mac addy....

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Commented:
Hi Nobus

This page http://www.kbc.be/ is SSL 3.0, RC4 with 128 bit encryption (High); RSA with 1024 bit exchange.
It is an Secure https site. This is a direct link > https://www.kbc.be/IPA/D9e01 <

Check in Internet Explorer settings under advanced tab. Click restore defaults. On the Content tab, click Clear SSL State. Reboot.

System requirements for this site.

""Systeemvereisten SSL3 (is standaard aanwezig en aangevinkt in de browser) Java-technologie""
Java Virtual Machine Microsoft >> http://static.kbc.be/images/pdf/javavirtualmachine/msjavx86.exe
Sun Java >> http://static.kbc.be/images/KBCOnline/j2re-1_4_2-windows-i586.exe
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Author Commented:
kcarrim,
i emptied the ssl cache, and reset to defaults, rebooted -> same problem
with the direct link however i can access it.
i checked, ssl 3 is on

any suggestions?
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Commented:
nobus did you install the Windows Script engine, still having the java problems ??
for network connection problem, have you read here yet ??

You cannot create a network connection in Windows XP
http://support.microsoft.com/default.aspx?scid=kb;en-us;329441
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Author Commented:
yes, i installed itn but no result.
Did you see the post above shehar?
I will try the networt connection link now.
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Commented:
i read you posts.... couldn't find any mentioning about the script engine.... may be im getting blind day by day =\
tell me one hting.... do you any other browser installed on the machine? is it also not able to view the bank website and other java sites ??
and did you install MS Java or Sun Java ??
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Author Commented:
script engine : maybe forgot to mention, but be assured, i do everything you say, or i ask explanation !
No other browser, MSjava installed ok.
Still the same though. (after windows update)
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Author Commented:
ideas?

dig man, dig !
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Commented:
you are running XP... why dont you try Sun Java :-?
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Author Commented:
ok, i will try it.
i think i should uninstall MSjava first? how? with the tool   MSJVM Removal Tool 1.0a.exe   ?
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Commented:
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Author Commented:
i installed the sun java; but the reult = 0, still the same problem
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Commented:
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Author Commented:
i already tested it on this site, without result :

http://www.virtualmachine.tk
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Author Commented:
result = cannot find page
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Commented:
nobus.... cant you try to install netscape or mozilla to check for the java problems there...... atleast we will come to know that Java is not working or IE is not working!!
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Commented:
Run SFC. Find the ie.inf file located in Windows\Inf folder.
Right click the ie.inf file and click Install on the context menu.
Reboot the computer when the file copy process is complete.

Reinstalling Internet Explorer > http://support.microsoft.com/default.aspx?kbid=318378

Also you can download and run Diagnostic Tool for the Microsoft VM
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Author Commented:
kcarrim : i already ran SFC, and uninstalled / installed IE from Add / remove soft; but what do you mean with :

>>>>    Run SFC. Find the ie.inf file located in Windows\Inf folder.
Right click the ie.inf file and click Install on the context menu.   <<<<  is that part of running sfc, or something else?

Will try the diagnostic tool
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Commented:
>>Find the ie.inf file located in Windows\Inf folder. Right click the ie.inf file and click Install on the context menu.<<

This is another way of reinstalling Internet Explorer, after SFC has run.
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Author Commented:
just ended running the VM diagnostic tool; everything looks ok, except :

Microsoft VM-afhankelijkheidsrapport - jennes-uw5cbgct
Starttijd: 27/11/2004 9:13:59
Eindtijd: 27/11/2004 9:32:05
Tijdsduur: 0.0:18:5.999

Bestandsnaam
C:\Documents and Settings\test\Mijn documenten\j2re-1_4_2-windows-i586.exe
C:\Documents and Settings\test\Mijn documenten\MSJavWU_8073687b82d41db93f4c2a04af2b34d.exe
C:\Documents and Settings\test\Mijn documenten\unmsjvm.exe
C:\Documents and Settings\test\Mijn documenten\Mijn muziek\unmsjvm.exe
C:\Program Files\Diagnostic Tool for the Microsoft VM\JavaDiag.exe
C:\Program Files\Diagnostic Tool for the Microsoft VM\JDWizard.exe
C:\Program Files\Internet Explorer\iedetect.dll
C:\Program Files\Java\j2re1.4.2\bin\axbridge.dll
C:\Program Files\Java\j2re1.4.2\bin\jpicom32.dll
C:\Program Files\Java\j2re1.4.2\bin\jpiexp32.dll
C:\Program Files\Java\j2re1.4.2\bin\jpins6.dll
C:\Program Files\Java\j2re1.4.2\bin\jpins7.dll
C:\Program Files\Java\j2re1.4.2\bin\jpinsp.dll
C:\Program Files\Java\j2re1.4.2\bin\jpishare.dll
C:\Program Files\Java\j2re1.4.2\bin\NPJava11.dll
C:\Program Files\Java\j2re1.4.2\bin\NPJava12.dll
C:\Program Files\Java\j2re1.4.2\bin\NPJava13.dll
C:\Program Files\Java\j2re1.4.2\bin\NPJava14.dll
C:\Program Files\Java\j2re1.4.2\bin\NPJava32.dll
C:\Program Files\Java\j2re1.4.2\bin\NPJPI142.dll
C:\Program Files\Java\j2re1.4.2\bin\NPOJI610.dll
C:\Program Files\Java\j2re1.4.2\bin\RegUtils.dll
C:\Program Files\Microsoft Visual Studio\Common\IDE\IDE98\HTMED.DLL
C:\Program Files\Microsoft VM\msjavx86.exe
C:\tmp\msjavx86.exe
C:\WINDOWS\$hf_mig$\KB834707\SP2QFE\browseui.dll
C:\WINDOWS\$hf_mig$\KB834707\SP2QFE\mshtml.dll
C:\WINDOWS\$hf_mig$\KB834707\SP2QFE\shdocvw.dll
C:\WINDOWS\$hf_mig$\KB834707\SP2QFE\urlmon.dll
C:\WINDOWS\$hf_mig$\KB834707\update\update.exe
C:\WINDOWS\$hf_mig$\KB834707\update\spcustom.dll
C:\WINDOWS\$NtServicePackUninstall$\browseui.dll
C:\WINDOWS\$NtServicePackUninstall$\corpol.dll
C:\WINDOWS\$NtServicePackUninstall$\iesetup.dll
C:\WINDOWS\$NtServicePackUninstall$\msado15.dll
C:\WINDOWS\$NtServicePackUninstall$\mshtml.dll
C:\WINDOWS\$NtServicePackUninstall$\mshtmled.dll
C:\WINDOWS\$NtServicePackUninstall$\occache.dll
C:\WINDOWS\$NtServicePackUninstall$\shdocvw.dll
C:\WINDOWS\$NtServicePackUninstall$\sprs0413.dll
C:\WINDOWS\$NtServicePackUninstall$\urlmon.dll
C:\WINDOWS\$NtServicePackUninstall$\webcheck.dll
C:\WINDOWS\$NtServicePackUninstall$\xpsp1res.dll
C:\WINDOWS\$NtUninstallKB834707$\browseui.dll
C:\WINDOWS\$NtUninstallKB834707$\mshtml.dll
C:\WINDOWS\$NtUninstallKB834707$\shdocvw.dll
C:\WINDOWS\$NtUninstallKB834707$\urlmon.dll
C:\WINDOWS\$NtUninstallKB834707-IE6SP1-20040929.091901$\browseui.dll
C:\WINDOWS\$NtUninstallKB834707-IE6SP1-20040929.091901$\mshtml.dll
C:\WINDOWS\$NtUninstallKB834707-IE6SP1-20040929.091901$\shdocvw.dll
C:\WINDOWS\$NtUninstallKB834707-IE6SP1-20040929.091901$\urlmon.dll
C:\WINDOWS\ServicePackFiles\i386\browseui.dll
C:\WINDOWS\ServicePackFiles\i386\corpol.dll
C:\WINDOWS\ServicePackFiles\i386\iepeers.dll
C:\WINDOWS\ServicePackFiles\i386\iesetup.dll
C:\WINDOWS\ServicePackFiles\i386\mshtml.dll
C:\WINDOWS\ServicePackFiles\i386\mshtmled.dll
C:\WINDOWS\ServicePackFiles\i386\occache.dll
C:\WINDOWS\ServicePackFiles\i386\shdocvw.dll
C:\WINDOWS\ServicePackFiles\i386\sprs0413.dll
C:\WINDOWS\ServicePackFiles\i386\sprt0413.dll
C:\WINDOWS\ServicePackFiles\i386\urlmon.dll
C:\WINDOWS\ServicePackFiles\i386\webcheck.dll
C:\WINDOWS\system32\clspack.exe
C:\WINDOWS\system32\jdbgmgr.exe
C:\WINDOWS\system32\jview.exe
C:\WINDOWS\system32\wjview.exe
C:\WINDOWS\system32\browseui.dll
C:\WINDOWS\system32\corpol.dll
C:\WINDOWS\system32\dx3j.dll
C:\WINDOWS\system32\iepeers.dll
C:\WINDOWS\system32\iesetup.dll
C:\WINDOWS\system32\javacypt.dll
C:\WINDOWS\system32\JAVALE.DLL
C:\WINDOWS\system32\javaprxy.dll
C:\WINDOWS\system32\javart.dll
C:\WINDOWS\system32\jit.dll
C:\WINDOWS\system32\msawt.dll
C:\WINDOWS\system32\mshtml.dll
C:\WINDOWS\system32\mshtmled.dll
C:\WINDOWS\system32\msjava.dll
C:\WINDOWS\system32\msjdbc10.dll
C:\WINDOWS\system32\occache.dll
C:\WINDOWS\system32\shdocvw.dll
C:\WINDOWS\system32\urlmon.dll
C:\WINDOWS\system32\vmhelper.dll
C:\WINDOWS\system32\webcheck.dll
C:\WINDOWS\system32\xpsp1res.dll
C:\WINDOWS\system32\xpsp2res.dll
C:\WINDOWS\system32\dllcache\browseui.dll
C:\WINDOWS\system32\dllcache\corpol.dll
C:\WINDOWS\system32\dllcache\iepeers.dll
C:\WINDOWS\system32\dllcache\iesetup.dll
C:\WINDOWS\system32\dllcache\mshtml.dll
C:\WINDOWS\system32\dllcache\mshtmled.dll
C:\WINDOWS\system32\dllcache\occache.dll
C:\WINDOWS\system32\dllcache\shdocvw.dll
C:\WINDOWS\system32\dllcache\sprs0413.dll
C:\WINDOWS\system32\dllcache\sprt0413.dll
C:\WINDOWS\system32\dllcache\urlmon.dll
C:\WINDOWS\system32\dllcache\webcheck.dll
D:\Program Files\Macromedia\Dreamweaver\Dreamweaver MX 2004\Configuration\Generator\bin\jflashgen.dll
D:\Program Files\Macromedia\Dreamweaver\Dreamweaver MX 2004\JVM\bin\ActPanel.dll
D:\Program Files\Macromedia\Dreamweaver\Dreamweaver MX 2004\JVM\bin\jpins32.dll
D:\Program Files\Macromedia\Dreamweaver\Dreamweaver MX 2004\JVM\bin\jpishare.dll
D:\Program Files\Macromedia\Dreamweaver\Dreamweaver MX 2004\JVM\bin\npjava11.dll
D:\Program Files\Macromedia\Dreamweaver\Dreamweaver MX 2004\JVM\bin\npjava12.dll
D:\Program Files\Macromedia\Dreamweaver\Dreamweaver MX 2004\JVM\bin\NPJava131_02.dll
D:\Program Files\Macromedia\Dreamweaver\Dreamweaver MX 2004\JVM\bin\npjava32.dll
D:\Program Files\Macromedia\Dreamweaver\Dreamweaver MX 2004\JVM\bin\NPOJI600.dll
D:\Program Files\Macromedia\Dreamweaver\Dreamweaver MX 2004\JVM\bin\beans.ocx
F:\Documents and Settings\Papa\Mijn documenten\Mijn eBooks\IEFix.exe

Bestandsfout
Bestandsnaam Foutbeschrijving
C:\WINDOWS\$NtUninstallKB824141$\user32.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB826939$\cryptsvc.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB826939$\hhsetup.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB826939$\itss.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB826939$\winsrv.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB826942$\dhcpcsvc.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB826942$\netshell.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB826942$\wzcdlg.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB826942$\wzcsapi.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB826942$\wzcsvc.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828035$\msgsvc.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828035$\wkssvc.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\comrepl.exe Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\migregdb.exe Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\catsrv.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\catsrvut.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\clbcatex.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\clbcatq.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\colbact.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\comadmin.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\comsvcs.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\comuid.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\es.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\msdtcprx.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\msdtctm.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\msdtcuiu.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\mtxclu.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\mtxoci.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\ole32.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\rpcrt4.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\rpcss.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\txflog.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB833998$\shell32.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB833998$\sxs.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\helpctr.exe Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\callcont.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\cmdevtgprov.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\evtgprov.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\gdi32.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\h323msp.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\ipnathlp.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\lsasrv.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\mf3216.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\msasn1.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\msgina.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\mst120.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\netapi32.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\nmcom.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\rtcdll.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\schannel.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\dao360.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\expsrv.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\msexch40.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\msexcl40.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\msjet40.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\msjetol1.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\msjetoledb40.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\msjint40.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\msjter40.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\msjtes40.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\msltus40.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\mspbde40.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\msrd2x40.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\msrd3x40.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\msrepl40.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\mstext40.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\mswdat10.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\mswstr10.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\msxbde40.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\vbajet32.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB839645$\fldrclnr.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB839645$\shell32.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB839645$\shlwapi.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB839645$\sxs.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB839645$\xpsp2res.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallQ828026$\wmpcore.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallQ828026$\msdxm.ocx Toegang geweigerd.

Terug naar boven

Visual J++ Class-rapport - jennes-uw5cbgct
Starttijd: 27/11/2004 9:32:05
Eindtijd: 27/11/2004 9:38:17
Tijdsduur: 0.0:6:12.0

Bestandsnaam
C:\Documents and Settings\test\Mijn documenten\JVMClean\edu\stanford\ejalbert\BrowserLauncher.class
C:\Program Files\Diagnostic Tool for the Microsoft VM\JavaDiag.exe
C:\WINDOWS\$hf_mig$\KB834707\SP2QFE\mshtml.dll
C:\WINDOWS\$NtServicePackUninstall$\msado15.dll
C:\WINDOWS\$NtServicePackUninstall$\mshtml.dll
C:\WINDOWS\$NtUninstallKB834707$\mshtml.dll
C:\WINDOWS\$NtUninstallKB834707-IE6SP1-20040929.091901$\mshtml.dll
C:\WINDOWS\ServicePackFiles\i386\mshtml.dll
C:\WINDOWS\system32\javaprxy.dll
C:\WINDOWS\system32\msawt.dll
C:\WINDOWS\system32\mshtml.dll
C:\WINDOWS\system32\msjava.dll
C:\WINDOWS\system32\msjdbc10.dll
C:\WINDOWS\system32\dllcache\mshtml.dll
D:\Program Files\Macromedia\Dreamweaver\Dreamweaver MX 2004\Configuration\Generator\bin\jflashgen.dll

Bestandsfout
Bestandsnaam Foutbeschrijving
C:\WINDOWS\$NtUninstallKB824141$\user32.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB826939$\cryptsvc.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB826939$\hhsetup.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB826939$\itss.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB826939$\winsrv.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB826942$\dhcpcsvc.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB826942$\netshell.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB826942$\wzcdlg.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB826942$\wzcsapi.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB826942$\wzcsvc.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828035$\msgsvc.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828035$\wkssvc.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\comrepl.exe Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\migregdb.exe Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\catsrv.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\catsrvut.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\clbcatex.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\clbcatq.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\colbact.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\comadmin.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\comsvcs.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\comuid.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\es.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\msdtcprx.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\msdtctm.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\msdtcuiu.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\mtxclu.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\mtxoci.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\ole32.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\rpcrt4.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\rpcss.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB828741$\txflog.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB833998$\shell32.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB833998$\sxs.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\helpctr.exe Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\callcont.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\cmdevtgprov.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\evtgprov.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\gdi32.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\h323msp.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\ipnathlp.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\lsasrv.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\mf3216.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\msasn1.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\msgina.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\mst120.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\netapi32.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\nmcom.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\rtcdll.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB835732$\schannel.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\dao360.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\expsrv.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\msexch40.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\msexcl40.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\msjet40.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\msjetol1.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\msjetoledb40.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\msjint40.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\msjter40.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\msjtes40.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\msltus40.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\mspbde40.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\msrd2x40.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\msrd3x40.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\msrepl40.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\mstext40.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\mswdat10.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\mswstr10.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\msxbde40.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB837001$\vbajet32.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB839645$\fldrclnr.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB839645$\shell32.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB839645$\shlwapi.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB839645$\sxs.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallKB839645$\xpsp2res.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallQ828026$\wmpcore.dll Toegang geweigerd.
C:\WINDOWS\$NtUninstallQ828026$\msdxm.ocx Toegang geweigerd.

Terug naar boven

0

Author Commented:
....and Mozilla does not exist in Dutch up to now
0

Commented:
Did you check System Account Permissions?? How many user accounts? Try logging in as Administrator and see if the problem persists. It could be caused be a corrupted registry / user account.
0

Author Commented:
there are six accounts, 5 of them have administrator privileges, and i created a test account with adm priv.
I did that already before posting the question.
Still the same problem.
i do not know if it has a relevance to this issue, but when i look at my network connections, i see nothing, even if i was able to finish the wizard, and created a connection in the workgroup HOME
0

Author Commented:
Oh yes, and i tried already another NIC card and cable, and the router is powered off/on daily.
0

Author Commented:
and i deleted the client, service and protocol, and reinstalled them
0

Commented:
nobus can you Try what is suggested in the Accepted Answer here >> http://www.experts-exchange.com/Operating_Systems/WinXP/Q_21203291.html
0

Author Commented:
i did unregister register for all the commands; no change is perceptible.
Do you think the fact i see no network connections is linked to the restricted internet access?
0

Commented:
It could be. What server do you have? Linux, Windows?
0

Author Commented:
No server, windows xp pro running
0

Commented:
Try this link and see if you can access the site.
https://e.absa.co.za/cashfocus/signon.jsp
0

Author Commented:
i can access that site
0

Commented:
Post the errors in the event log referring to DCOM. What about going to windows update? Have you tried updating XML Parser?
0

Commented:
0

Author Commented:
kcarrim, xml parser does not exist in Dutch; should i install it anyway?
i do not see any dcom errors, but i see service control manager error 7023
0

Author Commented:
kcarrim, i found a test page for accessing the bank page; it claims  :
-settings for javascript are correct
-BUT jreversionchecker notinited
does that ring a bell?
0

Commented:
0

Author Commented:
>>> what info do you want, and where can i find it?
I am installing the parser now
0

Commented:
This is an example >
Event ID: 7023
Source: Service Control Manager
The World Wide Web Publishing Service service terminated with the following error: The parameter is incorrect.

As in article > http://support.microsoft.com/?scid=http://support.microsoft.com%2Fservicedesks%2Fbin%2Fkbsearch.asp%3Farticle%3D327649
0

Author Commented:
7023 code : IPSEC service stopped with error code :
there is another address used that is incompatible with the asked protocol
That was on 11/29; Now i do not see those error codes (i reinstalled SP2)The last error i got was :
7000 : The CAM 3200 WDM video capture service cannot start because of following error :
cannot start service because it is disabled, or has no enabled devices connected

However, in services i cannot find the service control manager
0

Commented:
The IPSEC service is an IP Security service as you know.

Check your netork IP/TCP configuration under advanced, option, tcp/ip filtering. Make sure filtering is unchecked.
Also remoce NETBUI protocol.

Configure User Rights for this service.
http://support.microsoft.com/default.aspx?scid=kb;en-us;314357&Product=winxp

Configure The CAM 3200 WDM video capture service to run manual or disabled.

The way i see it, is that you are using a network protocol or protocol setting which is causing this.

Virus free?
Java Installed?
XML Parser Installed?
Windows Update?
0

Commented:
>>Also remoce NETBUI protocol.<<

Mistyped!! Meant :"Also remove NETBUI protocol"
0

Author Commented:
tcp/ip filtering unchecked, No Netbui protocol

>>>>   Configure User Rights for this service    <<< there is nothing to configure when i open MMC

Updates : virus free : NAV installed, ran adaware, spybot,  (all updated) Hijackthis
Java installed (will do it again)
XML parser installed >> no visible change
Cannot access windows update pages : it opens the page (you can see it for 1 sec) and gives :
windows found an error and cannot display the page

Thank you for staying with me ! (where is SheharyaarSahil ?) we lost him somewhere?
0

Commented:
Do you have an error code? >>windows found an error and cannot display the page<<
0

Author Commented:
No, it does not give an error code, and the links provided do not open either....  :-(
0

Commented:
OK. I will post the information from the links here.

1. If your computer is multiple-homed, disable the NetBEUI protocol that is bound to one of the network adapters.

For additional information about how to disable the NetBEUI protocol, click the article numbers below to view the articles in the Microsoft Knowledge Base:
197157 Workstation Service Does Not Start
103470 NetBIOS Name Conflicts When NetBEUI Used on Multiple NICs
If you continue to receive the event ID messages that are described in the "Symptoms" section of this article after you disable the NetBEUI protocol, go to step 2.
2. Determine if the WINS database contains static mappings.

If a static entry exists, remove it, and then restart the computer. For additional information about how to remove static WINS entries, click the article number below to view the article in the Microsoft Knowledge Base:
177140 How to Remove Static WINS Entries from All WINS Servers
If you continue to receive the event ID messages that are described in the "Symptoms" section of this article after you remove the static WINS entries, go to step 3.
3. Disconnect the network cable from the computer, and then restart the computer.

If you no longer receive the event ID messages that are described in the "Symptoms" section of this article, investigate possible network issues. For example, remove or disable the network components one by one to isolate the cause of this behavior, and then test to determine whether the event ID messages occur again.

HKEY_LOCAL_MACHINE\Software\Microsoft\Rpc\Internet
1. Click Start, click Run, type regedt32 in the Open box, and then click OK. This starts Registry Editor.
2. In Registry Editor, expand HKEY_LOCAL_MACHINE.
3. Under HKEY_LOCAL_MACHINE, double-click Software, double-click Microsoft, and then double-click Rpc.
4. Under RPC, select Internet.
5. On the Edit menu, click Delete to delete the key.
6. On the File menu, click Exit to close Registry Editor.
7. Click Start, and then click Shut Down. Select Restart in the list, and then click OK to restart the computer.
If you must control which ports MSDTC dynamically allocates for incoming communication, you must increase the number of ports that are specified under that registry key: 1. Click Start, click Run, type regedt32 in the Open box, and then click OK. This starts Registry Editor.
2. In Registry Editor, expand HKEY_LOCAL_MACHINE.
3. Under HKEY_LOCAL_MACHINE, double-click Software, double-click Microsoft, and then double-click Rpc.
4. Under RPC, select Internet.
5. In the right pane, double-click Ports.
6. In the Multi-String Editor dialog box, increase the range of specified ports. For example, if the current range is from 10000-15000, which allocates 5,000 ports, you can change the range to 10000-20000 to allocate 10,000 ports.For additional information, click the article number below to view the article in the Microsoft Knowledge Base:
250367 INFO: Configuring Microsoft Distributed Transaction Coordinator (DTC) to Work Through a Firewall
7. On the File menu, click Exit to close Registry Editor.
8. Click Start, and then click Shut Down. Select Restart in the list, and then click OK to restart the computer.

By default, the Internet key and its values under HKEY_LOCAL_MACHINE\Software\Microsoft\Rpc do not appear in the registry. If this key exists, it was probably added to specify the ports that the MSDTC allocates. This is most frequently done to permit MSDTC to work through a firewall.

0

Commented:
Do this quickly. Remove TCP/IP protocol. Restart pc. Add TCP/IP protocol. Configure static ip address if applicable. Restart. Now try Windows Update.
0

Commented:
I think we have a solution!!
Internet Explorer 6 SP1 Update: Page Cannot Be Displayed Error During SSL 3.0 Server Session Timeout

0

Commented:
WORKAROUND
To work around this problem, On the client, set the MaxConnectionsPerServer value to 1.

WinInet limits connections to a single HTTP 1.0 server to four simultaneous connections. Connections to a single HTTP 1.1 server are limited to two simultaneous connections. The HTTP 1.1 specification (RFC2616) mandates the two-connection limit. The four-connection limit for HTTP 1.0 is a self-imposed restriction that coincides with the standard that is used by a number of popular Web browsers.

The only evidence of this limitation to your application is that calls such as HttpSendRequest and InternetOpenURL appear to take longer to complete because they wait for previous connections to be freed up before their requests are sent.

You can configure WinInet to exceed this limit by creating and setting the following registry entries:

Note By changing these settings, you cause WinInet to go against the HTTP protocol specification recommendation. You should only do this if absolutely necessary and then you should avoid doing standard Web browsing while these settings are in effect:
HKEY_CURRENT_USER\Software\Microsoft\Windows\CurrentVersion\Internet Settings

MaxConnectionsPerServer REG_DWORD (Default 2)
Sets the number of simultaneous requests to a single HTTP 1.1 Server

MaxConnectionsPer1_0Server REG_DWORD (Default 4)
Sets the number of simultaneous requests to a single HTTP 1.0 Server
These settings are made for a particular user and will have no affect on other users who log on to the computer.

In Internet Explorer 5, it is possible to change the connection limit programmatically by calling the InternetSetOption function on NULL handle with the following flags (note that it will change connection limit for the whole process):
INTERNET_OPTION_MAX_CONNS_PER_SERVER INTERNET_OPTION_MAX_CONNS_PER_1_0_SERVER
Note If the process has established a connection to a server, if you change the connection limit by calling InternetSetOption, the function does not have any effect to subsequent connections on the same server. This occurs even if a prevous connection is disconnected prior to the call to InternetSetOption. Connection limit does affect all other servers
0

Commented:
Also you can disable SSL2 and SSL3 setting in Internet options, Advanced, Security
0

Author Commented:
ok update on post from 3:22
1- there is no NETBUI protocol
2- WINS does not contain anything
3-    >>>>>    HKEY_LOCAL_MACHINE\Software\Microsoft\Rpc\Internet
1. Click Start, click Run, type regedt32 in the Open box, and then click OK. This starts Registry Editor.
2. In Registry Editor, expand HKEY_LOCAL_MACHINE.
3. Under HKEY_LOCAL_MACHINE, double-click Software, double-click Microsoft, and then double-click  Rpc.
4. Under RPC, select Internet.     <<<<<

--==--==   >>There is no internet entry here !!

update from post 3:39

>>>   Internet Explorer 6 SP1 Update   <<<  it does not install, since it is IE 6.0 SP2    :-(

Thanks for all this work, i will try the remaining now.

Is it correct that there is no Internet entry, as said under 3- ??
Also, it is a standalone computer i'm repairing for a friend, and i have mine here to download everything....
0

Author Commented:
SSL 2 and 3 disabled, no joy.
Will now remove tcp ip as per post 3:23
0

Author Commented:
you cannot remove tcp/ip from the network settings; did you mean anything else maybe?
0

Commented:
Just disable it. Restart.

A question.
Your pc connects with broadband? Are you using a static IP? Set the settings on the other pc you are repairing to be the same as your pc. Try to connect and tell me what error(s) you receive.
0

Author Commented:
They are both set to automatic.
How can i disable tcp/ip protocol? it gives no option to do so under network
0

Commented:
Remove the checkbox
0

Commented:
What NIC card is in this system??
0

Author Commented:
>>>   Remove the checkbox    <<<<   what checkbox and where?

>>>   What NIC card is in this system??    <<<  it is onboard , motherboard is Soltek SL-75MRN; NVIDIA NForce

but i tried already with a known good card from Compaq Netintelligent
0

Commented:
Sorry :) In connection setting, properties, Internet protocol, remove the tick from this check box, not the check box itself. Did you disable the windows firewall or check the settings?
0

Author Commented:
update : unchecked the tcp/ip protocaol and followed your instructions as per post 3:23
if microsoft tcp/ip protocol version 6 is installed, i have no internet connectivity;
if i install tcp/ip normally, i HAVE ACCESS ! !
0

Author Commented:
Ok, there were no updates available, as SP 2 is installed.
access to the www.kbc.be is still impossible; when i open the page, it displays : you will now display info via a secure channel, when i click OK, -->> the page cannot be displayed
So, we have a little progress at least.
0

Commented:
Hi

Please reset all internet explorer settings to default. Uninstall Java. See if you can access the site without Sun Java installed.
I found this log file from my antivirus, dated about 2 months back. After this i unistalled Sun Java and i am browsing the internet withou Sun Java installed.

Maybe it shines some ligt on this problem.

Log List
"Time","Scan Type","Source Type","Virus Name","Infected Source","First Action","Second Action"
"09:13","Manual Scan","File","JAVA_BYTEVER.A-1","C:\Documents and Settings\admin\Application Data\Sun\Java\Deployment\cache\javapi\v1.0\file\Gummy.class-713939f3-6d05ae92.class","Clean Unsuccessful","Quarantine Successful"
"09:13","Manual Scan","File","JAVA_BYTEVER.A","GetAccess.class (C:\Documents and Settings\admin\Application Data\Sun\Java\Deployment\cache\javapi\v1.0\jar\clsld.jar-34982b9e-3f84fdde.zip)","Clean Unsuccessful","Quarantine Unsuccessful"
"09:13","Manual Scan","File","JAVA_BYTEVER.A","Installer.class (C:\Documents and Settings\admin\Application Data\Sun\Java\Deployment\cache\javapi\v1.0\jar\clsld.jar-34982b9e-3f84fdde.zip)","Clean Unsuccessful","Quarantine Unsuccessful"
"09:13","Manual Scan","File","---","C:\Documents and Settings\admin\Application Data\Sun\Java\Deployment\cache\javapi\v1.0\jar\clsld.jar-34982b9e-3f84fdde.zip","Clean Unsuccessful","Quarantine Successful"
"13:21","Real-time Scan","File","Possible_Virus","C:\Program Files\eDonkey2000\plugins\BTPlugin.dll","Clean Unsuccessful","Quarantine Successful"
0

Commented:
If this fails, i think we should start from scratch. Format, install XP. Visit www.kbc.be. If successful, install Service pack, visit www.kbc.be, and so on until we can pinpoint which app is causing this. To me it seems that Java is the culprit on this system.
0

Author Commented:
That was what i thought from the beginning, however i could not find what was wrong (see the start of this thread) : i uninstalled javaVM, installed it, tried to use sun java etc...

Thanks for your help anyway, i will close this thread in a couple of days, so i can give you the latest info, which is the least i can do for your efforts !
0

Commented:
Always here to help, or at least to give my comments!!
You asked previously on another post if i am South African speaking.
Ja ek is Afrikaans!
0

Commented:
Hey,

I've been folowwing along, I haven't abondoned this yet either, I don't like to interupt when someone is on a roll: kcarrim:-)

Have either of you guys seen these?

http://www.lavasoftsupport.com/index.php?showtopic=14501

http://www.microsoft.com/technet/security/bulletin/MS03-011.mspx

It is the most likely cause of the problem as I see it noqw...

Cheers,

Jatcan
0

Commented:

Cheers,

Jatcan
0

Author Commented:
Actually, it was not, but i put it there to eliminate some buggers
0

Commented:
Glad you joined in Jatcan. I've already seen this articles, that's why i posted (12/01/2004 10:26AM SAST). I was also  thinking of disabling system restore, and doing a cleanmgr.exe and removing previous system restore points.

Nobus, have you tried running msconfig and disabling all your startup items to see which app is hacking your system?
0

Author Commented:
Hi guys, i'm doing a backup-install-restore procedure; could not wai any longer.
0

Commented:
I agree. This one has kept us busy!!
0

Author Commented:
I tried a repair install also : Did not work either...
0

Commented:
Well, backup all data, format and start over with new installation.
0

Author Commented:
Yes, that is what i'm busy with today....
5 accounts
1user has 6 e-mail accounts ...and so on ...
0

Author Commented:
No one solved this, but there was so much support and effort from SheryaarSahil and Kcarrim that they deserve the excellence in helping !

kcarrim  : en ik ben een vlaamse jongen (geweest)
0

## Featured Post

• 63
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Tackle projects and never again get stuck behind a technical roadblock.


text:
# Behaviour of Primes under Regular Coefficient Extensions

Let $K\hookrightarrow K'$ be a regular extension of fields, and $K[x_{1},\cdots,x_{n}]\hookrightarrow K'[x_{1},\cdots,x_{n}]$ the corresponding ring extension. Does every prime ideal of the first ring expand to a prime ideal in the second?

-

A field extension $K \to K'$ is regular if and only if for every $K$-algebra $A$ which is an integral domain the $K'$-algebra $A' := A \times_K K'$ is an integral domain (Bourbaki, Algebra, Chap. V, §17, No.3). Applying this to $A = K[x_1,\dots,x_n]/{\mathfrak p}$ for a prime ideal ${\mathfrak p}$ we obtain $A' = K'[x_1,\dots,x_n]/{\mathfrak p}K'[x_1,\dots,x_n]$. Thus ${\mathfrak p}K'[x_1,\dots,x_n]$ is a prime ideal.

-
Yes, and it is an astonishing thing that this fact doesn't appear in other classical books of algebra (I went to Lang's one, and he shows the result only for finite extensions and certain kind of primes. Wikipedia doesn't make any reference to things like this, and other sources don't even talk about regular extensions). Thanks for the reference. –  user12940 Mar 30 '11 at 16:31

format: plain


text:
# Hatched bars and bar-specific background in BarChart

I would like to diagonally hatch the bars in BarChart and to have three different background colors for the different bars, like this:

Any ideas how to reproduce this image? The closest post I found is here.

-
–  The Toad Oct 15 '13 at 4:35
@rm-rf The hatching part of this question is a duplicate indeed. The background part, however, is unique to this question. Therefore, I hesitate to vote to close. –  Sjoerd C. de Vries Oct 15 '13 at 6:29
@SjoerdC.deVries Fair enough. Changed comment to "Related" –  The Toad Oct 15 '13 at 7:05

With a bit of manual parameters:

barFilled[gap_, h_, seg_][{{xmin_, xmax_}, {ymin_, ymax_}}, ___] :=
Module[{width, line, yt, yb, lend},
{yb, yt} = Sort[{ymin, ymax}];
width = xmax - xmin;
line = Table[{{xmin, i}, {xmax, i + width}}, {i, yb, yt - width, h/seg}];
lend = line[[-1, 1, 2]];
line = {Line[line],
Line[Table[{{xmin + i, yb}, {xmax, yb + width - i}}, {i, h/seg, width, h/seg}]],
Line[Table[{{xmin, lend + i}, {xmax - (lend + width - yt) - i,yt}}, {i, h/seg, width + h/seg, h/seg}]]};
{{Opacity[.2], EdgeForm[], Rectangle[{xmin, -h}, {xmax + gap, h}]},
{CapForm["Butt"], line}, {FaceForm[], Rectangle[{xmin, ymin}, {xmax, ymax}]}}]

BarChart[{2, -1, 1.5, -3, 3, 2.5}, BarSpacing -> 2,
ChartElementFunction -> barFilled[.65, 3, 35], ChartStyle -> 61,
GridLines -> {None, Automatic}]

Like AimForClarity mentioned, to avoid empty strip, we could replace 0 with some dummy value + meta and define barFilled for that value. For example:

barFilled[gap_, h_, seg_][{{xmin_, xmax_}, {ymin_, ymax_}}, _, {None}] :=
{{Opacity[.2], EdgeForm[], Rectangle[{xmin, -h}, {xmax + gap, h}]}}

BarChart[{2, -1, 0, -2, 1, 2} /. {0 -> (1 -> None)}, BarSpacing -> 2,  ChartElementFunction -> barFilled[.65, 2, 35],
ChartStyle -> 61, GridLines -> {None, Automatic}]

-
Does the grid lines have to be on top of the charts and axes ticks labels? –  mmal Oct 15 '13 at 8:45
@mmal grid lines are behind bars. It's a side effect of setting FaceForm[]. If you don't want that, you can insert one more rectangle before drawing lines. For example, .., {FaceForm[White], Rectangle[{xmin, ymin}, {xmax, ymax}]}, {CapForm["Butt"], line}, ... –  halmir Oct 15 '13 at 12:14
@mmal To have grid lines on top of the charts and axes ticks labels one can use Method -> {"GridLinesInFront" -> True} option. –  Alexey Popkov Oct 15 '13 at 21:12
Thanks, the halmir's method does exactly what I was thinking about. Using Frame->True clips the grid lines to frame region. –  mmal Oct 16 '13 at 5:52
I hav not been able to get around this silly problem, that if one of the elements is 0 in the array, the barFilled function does not seem to be called and so there is an empty strip, any ideas how to fix this? –  AimForClarity Oct 19 '13 at 4:31


text:
# Toufik Mansour - Chalmers Research

The golden ratio – Lightroom videokurs LinkedIn Learning

1. Introduction. The well-known Fibonacci numbers. Fn=1. only think of the sum of the reciprocals of the Fibonacci numbers themselves which to The non-alternating series of the second degree has closed formulas for. Does such a function exist?

Luckily, a mathematician named Leonhard Euler discovered a formula for calculating any Fibonacci number. This formula was lost for about 100 years and was rediscovered by another mathematician named Jacques AN EXPLICIT FORMULA FOR FIBONACCI NUMBERS LEO GOLDMAKHER 1. INTRODUCTION At the heart of induction is the idea that to prove a predicate, it sufﬁces to be able to reduce any particular Binet's Formula is an explicit formula used to find the nth term of the Fibonacci sequence. It is so named because it was derived by mathematician Jacques Philippe Marie Binet, though it was already known by Abraham de Moivre. We can also use the derived formula below. This is the general form for the nth Fibonacci number. To begin our researchon the Fibonacci sequence, we will rst examine some sim-ple, yet important properties regarding the Fibonacci numbers.

It is simply the series of numbers which starts from 0 and 1 and then continued by the addition of the preceding two numbers. In this article, you will learn how to write a Python program to Fibonacci Series in C#. In case of fibonacci series, next number is the sum of previous two numbers for example 0, 1, 1, 2, 3, 5, 8, 13, 21 etc.

## DiVA - Sökresultat - DiVA Portal

In this article, we are going to discuss another formula to obtain any Fibonacci number in the sequence, which might (arguably) be easier to work with. The Formula. Let us define a function $F(x)$, such that it can be expanded in a power series like this $$F(x) = \sum_{n \ge 0}x^n F_n = x \cdot F_1 + x^2 \cdot F_2 + \cdots$$ In other words, we’ve just discovered that the Taylor series of this function has precisely the Fibonacci coefﬁ-cients: 1 1 x x2 = 1+x+2x2 +3x3 +5x4 +8x5 +13x6 +21x7 + The advantage of this is that the function on the right is explicitly about the Fibonacci numbers, while the 2021-04-07 · The Fibonacci numbers are the numbers in the following integer sequence. 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, ……..

### Arkitektur - Husmodeller designade av mig - Design och

Th = theorem transf = transformation. Beteckningar för matematiska fackområden.

Find a formula for Bn and prove it. tidskrift, Fibonacci Quarterly, som är helt ägnad Fibonaccitalen Fn (och de besläktade Lucastalen Ln,  27 dec.
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The formula for calculating the Fibonacci Series is as follows: F (n) = F (n-1) + F (n-2) where: F (n) is the term number.

F (n+1) = round ( F (n) Phi ) The round function applies to a number (whole or decimal) and changes it to an integer. It's easy to create all sorts of sequences in Excel.For example, the Fibonacci sequence.. 1.
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### MINI COOPER BONNET STRIPES HOOD VINYL DECAL

With Fibonacci series, the formula is not that evident. Psychologically human mind is less likely to attached ‘time’ to the numbers Fibonacci series. Many teams go further and instead of “points”, refer to more abstract things, such as “this task is 8 sunflower seeds of work”, or “we think the complexity is 5 puppies.” De esta manera, la fórmula explícita de la sucesión de Fibonacci tendrá la forma. f n = b ( 1 + 5 2 ) n + d ( 1 − 5 2 ) n {\displaystyle f_ {n}=b\left ( {\frac {1+ {\sqrt {5}}} {2}}\right)^ {n}+d\left ( {\frac {1- {\sqrt {5}}} {2}}\right)^ {n}} .

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### Fibonacci Numbers and the Golden Ratio - Bookboon

The next number is a sum of the two numbers before it. The 3rd element is (1+0) = 1 The 4th element is (1+1) = 2 The 5th element is (2+1) = 3. Fibonacci Series Formula. Hence, the formula for calculating the series is as follows: x n = x n-1 + x n-2; where x n is term number “n” x n-1 is the previous term (n-1) x The first two numbers of a Fibonacci series are 0 and 1. The rest of the numbers are obtained by the sum of the previous two numbers in the series. It means to say the nth digit is the sum of (n-1)th and (n-2)th digit.


text:
# Sentence Examples with the word echinodermata

Milne-Edwards removed the Polyzoa; the group was soon further thinned by the exclusion of the Protozoa on the one hand and the Entozoa on the other; while in 1848 Leuckart and Frey clearly distinguished the Coelenterata from the Echinodermata as a separate sub-kingdom, thus condemning the usage by which the term still continued to be applied to these two groups at least.

Vertebres) also used the term, as when he spoke of the Medusae as radiata medusaria et anomala; but he preferred the term Radiaria, under which he included Echinodermata and Medusae.


text:
Keine Ahnung, was das bedeuten soll? Keine Sorge, Permutation tests, which I'll be discussing in this post, aren't that widely used by econometricians. However, they shouldn't be overlooked.Let's begin with some background discussion to set the scene. This might seem a bit redundant, but it will help us to see how permutation tests differ from the sort ‘A simple position permutation was also used to generate random sequences.’ ‘The statistical significance of the values was estimated by permutation analysis using 1,000 replications.’ ‘All significance thresholds were determined empirically by permutation’ In this article, we will learn about the Introduction permutation group, and the types of permutation in discrete mathematics. Submitted by Prerana Jain, on August 17, 2018 .

Permutation Group. Let, X be a non-empty set. A permutation of X is a one-one function from X onto X.A group (G,*) is called a permutation group on a non-empty set X if the elements of G are a permutation of X and the Then, given a permutation π ∈Sn, it is natural to ask how “out of order” π is in comparison to the identity permutation. One method for quantifying this is to count the number of so-called inversion pairs in π as these describe pairs of objects that are out of order relative to each other. Deﬁnition 4.1.

(8 över 5) 8*7*6*5*4 = 6720 . Har jag räknat ut det rätt?

( ˌpɜːmjʊˈteɪʃən) n. 1.

It doesn't matter in what order we add our ingredients but if we have a combination to our padlock that is 4-5-6 then the order is extremely important. Permutation The number of ways to choose a sample of r elements from a set of n distinct objects where order does matter and replacements are not allowed. When n = r this reduces to n!, a simple factorial of n.

Det är också viktigt att förklara varför permutation behövs (skäl för ansökan). Vad är en permutation?
Områdesbehörighet 6

It's good to get everything out of your head into the system, but part of the system is also being honest about what is actionable. If you can't permutation - Translation to Spanish, pronunciation, and forum discussions. Principal Translations: Inglés: Español: permutation n noun: Refers to person, place, thing, quality, etc. (transformation) transformación nf nombre femenino: Sustantivo de género exclusivamente femenino, que lleva los artículos la o una en singular, y las o unas en plural. Exemplos: la mesa, una tabla.

L'ensemble S(X) des permutations de X est un groupe pour la loi de composition ∘, appelé groupe symétrique de X. Dans le cas particulier où X={1, …, n} avec n entier naturel, cet ensemble se note S n. 2019-01-28 · Also in this first permutation, D, E and F have times of 11, 11 and 13, respectively. This has an average of 11.6666. After calculating the mean of each group , we calculate the difference between these means. Permutation definition, the act of permuting or permutating; alteration; transformation. See more.
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An ordered ( re)arrangement of the elements of a (finite) set; a function that is both a  The arrangement of objects in a certain order is called a permutation. The number of ways to arrange eight things taken three at a time is written as P(8, 3) or as 8  6 days ago Permutations are commonly represented in disjoint cycle or array forms. Array Notation And 2-line Form. In the 2-line form, the elements and their  Improve your math knowledge with free questions in "Permutations" and thousands of other math skills. The main part of this file consists in the definition of permutation objects, i.e. the Permutation() method and the Permutation class.

Zero factorial or 0! Ways to arrange colors. Ways to pick officers. Practice A permutation is an arrangement, or listing, of objects in which the order is important. In previous lessons, we looked at examples of the number of permutations of n things taken n at a time. Permutation is used when we are counting without replacement and the order matters.
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Det är också viktigt att förklara varför ändringen behöver göras (skäl för ansökan). Förutsättningar för permutation. Handlingar som ska skickas till Kammarkollegiet … 2018-01-25 One could say that a permutation is an ordered combination. The number of permutations of n objects taken r at a time is determined by the following formula: $$P(n,r)=\frac{n!}{(n-r)!}$$ A permutation is an arrangement, or listing, of objects in which the order is important.


text:
# On the sufficiency of $c$-cyclical monotonicity for optimality of transport plans

created by pratelli on 20 Nov 2006
modified on 25 Sep 2010

[BibTeX]

Published Paper

Inserted: 20 nov 2006
Last Updated: 25 sep 2010

Journal: Math. Z.
Year: 2007

Abstract:

We consider a mass transport problem among Polish spaces, and we show that a transport plan concentrated in a $c-$cyclical monotone set is optimal if the cost function is continuous and possibly $+\infty$ valued; the same result is proved for a generic l.s.c. cost function in the case when the measures are purely atomic. This generalizes the previously known results.


text:
# Homework Help: Need to find c in a quadratic equation

1. Jun 11, 2012

### chomsky

1. The problem statement, all variables and given/known data

If α and $\frac{1}{αα}$are the roots of the equation $5x^{2}+13x+k$ then k will be:

a) 5
b) -5
c) 13
d) 1

2. Relevant equations

3. The attempt at a solution

I've tried multiplying both the roots to get $\frac{c}{a}$ and adding the roots to get $\frac{-b}{a}\frac{}{}$, and then I've tried to add the sum and the product of the roots on the LHS and corresponding to it, $\frac{c}{a}$ and $\frac{-b}{a}$ on the RHS. But I just can't get the answer, and I can't figure out how to solve this any differently. Any help or ideas on how to go about solving this type of question would be greatly appreciated.

2. Jun 11, 2012

### Infinitum

Hi chomsky!

Is the second root $1/\alpha$ or $1/\alpha^2$?

If it is the the first, the question would be really simple, as their product is

$$\alpha \cdot \frac{1}{\alpha} = \frac{k}{5}$$
What does this give you?

If the second, you won't get an answer matching your options. But you can use the relation from product of roots and substitute it in the equation from sum of roots to get a cubic equation in k.


text:
Here's the question you clicked on:

## 0213 Group Title A certain liquid has a vapor pressure of 92.0 Torr at 23.0 °C and 313.0 Torr at 45.0 °C. Calculate the value of ΔH°vap for this liquid. Calculate the normal boiling point of this liquid. How would I do this? Please help 7 months ago 7 months ago

• This Question is Closed
1. 0213 Group Title

@Rohitkhanna

2. petiteme Group Title

Should you use Clausius-Clapeyron equation?

3. 0213 Group Title

do I just solve for T2 and use the same values?

4. petiteme Group Title

Well, let the normal boiling point be T2

5. 0213 Group Title

wouldn't that just give me the T that is given in the question ?

6. petiteme Group Title

Nope. Sorry :/ I suck at explaining chemistry

7. 0213 Group Title

i just get a very small number

8. petiteme Group Title

What did you get for ΔH°vap?

9. RaphaelFilgueiras Group Title

im not good at chemistry but let's try

10. 0213 Group Title

43.55 kj/mol

11. petiteme Group Title

I used $\log\frac{ P2 }{ P1 }=\frac{ ΔH }{2.303R }*(\frac{ 1? }{ T1 }-\frac{ 1 }{ T2 })$

12. petiteme Group Title

Erase the ?

13. 0213 Group Title

what is v?

14. petiteme Group Title

I got 49.78kj

15. petiteme Group Title

Lol. I don't know if i'm right. Ignore me :))

16. RaphaelFilgueiras Group Title

volume i dont know if that's right , it's been i while i dont see chemistry

17. RaphaelFilgueiras Group Title

lol

18. 0213 Group Title

sing those number? i dont have V so i dont think i can use that

19. petiteme Group Title

You saw my equation?

20. 0213 Group Title

yea

21. petiteme Group Title

Have you tried it?

22. 0213 Group Title

yea...and i got 43.55...its ok..i will do the question tmr...im just really tired now

23. petiteme Group Title

Okies. Just close this question ^_^


text:
# How do you write 2,796,460,000 in scientific notation?

Mar 3, 2018

$2.80 \cdot {10}^{9}$

#### Explanation:

The scientific notation is expressed by a number rounded off to two decimal places and then multiplied by ${10}^{n}$, where $n$ is a natural number.

So here, we have the number $2 , 796 , 460 , 000$, or $2.796$ billion.

$1$ billion is the same as ${10}^{9}$.

So here, we got

$2.796 \cdot {10}^{9}$

Rounding off $2.796$ to two decimal places, we get $2.80$. So, the final answer will be

$2.80 \cdot {10}^{9}$


text:
# TJ-II:Impurity density and potential asymmetries

## Experimental campaign

2017 Spring

Figure 1. Numerical vs Experiment electron-root #45477 discharge: (a,b) Numerical impurity density asymmetry parameter $\alpha_{nZ}$ and the experimental radiation asymmetry parameter $\alpha_{rad}$ respectively at the toroidal plane $\phi=14.5^{\circ}$ that corresponds the SXR toroidal measurement plane. (c,d) Numerical impurity density asymmetry parameter $\alpha_{nZ}$ and the experimental radiation asymmetry parameter $\alpha_{rad}$ respectively at the toroidal plane $\phi=75.5^{\circ}$ that corresponds the Bolometery toroidal position. Note the numerical and experimental scale sare the same $[-0.38, 0.38]$. Since neon impurities were puffed at trave levels during the discharges, the numerical results in (a,c) have considered $Z_{I}=10$, i.e. they have assumed fully ionization of Ne on the whole effective radius [1]
Figure 2. Same as in figure 1. but considering the ion-root discharge #45469 [2]

## Proposal title

Impurity density and potential asymmetries

## Name and affiliation of proponent

José M García Regaña1, M. Ezzat1, B. van Milligen1, M. A. Ochando 1, F. Medina1, José Luis Velasco1, J. A. Alonso 1, I. Calvo 1, C. Hidalgo1, K. McKarthy1

1. Fusion National Laboratory, CIEMAT, 28040, Madrid, Spain

## Description of the activity, including motivation/objectives and experience of the proponent (typically one-two pages)

Neoclassical theory predicts a non-constant portion of the electrostatic potential over the flux surfaces [3], usually denoted by $\Phi_1=\Phi_1(\theta,\phi)$, with $\theta$ and $\phi$ the poloidal and toroidal angular coordinates. When this is taken into account the equilibrium density of the different species a present in the plasma varies according to their adiabatic response and can be written as: $n_{a0}=\left<n\right>\exp\left(-Z_{a}e\Phi_1/T_{a}\right)$, with $\left<...\right>$ the flux-surface-average. In TJ-II plasmas experiments and simulations [4] [5] [6] have shown that $e\Phi_1/T_{a}$ can take values from $O(0.01)$ to $O(0.1)$. Variations are predicted to be larger at the outer radii than at the inner core, and stronger in ECRH plasmas than in NBI plasmas. Under conditions with large $\Phi_1$ the impurities of moderate to high $Z$ should experience strong variations of their densities over the flux surfaces, increasing with $Z$. These, in turn, should result in an anisotropic radiation over each flux surface and consequently a radially asymmetric radiation pattern should follow.

In the present experiment the analysis of the radial profiles and time evolution of the plasma emissivity using the TJ-II bolometry system [7] after the inyection of some selected impurities by gas puffing is proposed. The experiment aims at studying the above-mentioned link between the radially assymetric emissivity and the measured and predicted $\Phi_1$. The measurement and evolution of $\Phi_1$ will be tracked during the discharges using the duplicated Langmuir probe system plasma floating potential measurements. Numerical calculations of $\Phi_1$ will be carried out with the neoclassical version of the code EUTERPE at different radial locations. The application of fluid tools is also foreseen for the comparison between simulations and with the experimental results.

## Description of required resources

The required signals to perform the analysis are:

• The time evolution of the plasma emissivity radial profile via tomographic reconstructions of the bolometry system signals.
• The time evolution of the plasma floating potential at the outer core region ($r/a\sim 0.9$).
• The time evolution of the line-averaged density $\left<n_e(t)\right>$ with interferometry.
• The radial profiles of electron density $n_{e}(r, t_0)$ and temperature at one time instant $t_0$ using Thomson Scattering (TS).
• The time evolution of the electron temperature profile $T_{e}(r,t)$ with Electron Cyclotron Emission (ECE), when available, calibrated with TS.
• The time evolution of the ion temperature in the core and in an outer radial position $T_i(r/a\sim 0.2,t)$ and $T_i(r/a\sim 0.8,t)$ with the Neutral Particle Analyzer (NPA).
• The time evolution of the radial electric field at the mid-outer resion ($r/a\sim 0.7-0.8$) with reflectometry.
• The time evolution of the electrostatic potential in the mid-outer region $\Phi(r/a\sim0.7,t)$ with the double Heavy Ion Beam Probe (HIBP).

Other constraints regarding the desired experimental conditions are:

• Good reproducibility of the plasma discharges to allow comparison across impurity and charge states $Z$. Scannig $T_e$ is also considered by the application of different ECH injected power.
• Good stationarity of plasma parameters at the instant where the impurities are injected is required in order to extract the stationary background emissivity from that produced by the injected impurity. Hence the study shall preferably be perform in ECRH plasmas.

## Preferred dates and degree of flexibility

Preferred dates: (format dd-mm-yyyy)

## References

1. M. Ezzat Advanced neoclassical impurity transport modelling with experimental comparison for TJ-II Master Thesis (2018)
2. M. Ezzat Advanced neoclassical impurity transport modelling with experimental comparison for TJ-II Master Thesis (2018)
3. H. Mynick Calculation of the poloidal ambipolar field in a stellarator and its effect on transport Phys. Fluids 27(8) 2086 (1984)
4. M A Pedrosa et al., Electrostatic potential variations along flux surfaces in stellarators Nucl. Fusion 55 052001 (2015)
5. B Liu et al. Direct experimental evidence of potential asymmetry in magnetic flux surfaces in stellarators to be submitted (2017)
6. J M Garcı́a-Regaña et al. Electrostatic potential variation on the flux surface and its impact on impurity transport Nuclear Fusion submitted (2017)
7. M. A. Ochando et al. Up-down and in-out asymmetry monitoring based on broadband radiation detectors Fusion Sci. and Technol. 50 313 (2006)


text:
# A Weak Form of Borsuk Conjecture

Problem: Let P be a polytope in $R^d$ with n facets. Is it always true that P can be covered by n sets of smaller diameter?

I also asked this question over mathoverflow, with some background and motivation.


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# Help decipher DC brushed motor ratings

I have two same sized DC brushed motors found in different variants of an appliance of the same brand. They are possibly equivalent, but they have different labels.

One is labelled with:

(Johnson Electric logo)
31348
3K3861

The other is labelled with:

3501-0011-01  REV C
CIM-2450-1
24 VDC  0.9 A
50 RPM /15 LB-IN  9-95

The diameter of the motors are 27.5mm, and length of the motor bodies is 32.5mm.

What does the last line, beginning with "50 RPM" mean? Surely it doesn't simply mean the nominal speed, since 50 RPM is way too slow. Does it have something to do with the concept of "motor regulation"? This online catalog meantions motor regulation in units that I am not sure about, e.g. on page 50, for motor model HC313G-001, it says Motor Regulations: 304.857 Rpm/m-Nm . Huh, is that rpm per millinewton-metre?

• Label on second motor suggests it has a gearbox attached, then 50rpm could make sense. Motor regulation suggests it slows down by 305rpm for every mN-m of load (from its no-noad speed of 6900 rpm) Mar 30, 2015 at 11:41
• Thank you Brian and Brad. It does make sense to me now. The second label was stuck on the motor can but actually refers to the motor+gearbox. BTW, does 1 mN-m mean 0.001 newton-metre? Mar 31, 2015 at 3:16
• Yes. 1 mN-m means 1 milli-Newton-meter, or 0.001 Newton-meter. Usually if the gearmotor is sold from the manufacturer and not as separate parts, the ratings refer to the gearmotor and not the motor by itself.
– Eric
Mar 31, 2015 at 4:18

Motor regulation is a figure of merit for DC motors. It can be thought of in a number of different ways. Some people like to think of it as the slope of the speed torque curve. What it tells you is the motor's ability to turn electrical power into mechanical power. It can be calculated by $\frac{R}{k_t^2}$, where $R$ is the terminal resistance of the motor and $k_t$ is the torque constant of the motor. A lower value indicates better heat conversion.
Some people also use a similar figure of merit called the motor constant ($K_m$). $K_m = \frac{k_t}{\sqrt{R}}$. As you can see, this is just the reciprocal of the square root of the motor regulation that I talked about in the previous paragraph.


text:
# Identity between $x=y+z$ and $\tan\left(\frac{\theta}{2}\right)=\tan\left(\frac{\nu}{2}\right)\tan\left(\frac{\pi/2-\epsilon}{2}\right)$

I would like to prove that (1) $$$$\tan\left(\frac{\theta}{2}\right)=\tan\left(\frac{\nu}{2}\right)\tan\left(\frac{\pi/2-\epsilon}{2}\right)$$$$

can transformed to (2) $$x=y+z,$$ where (3) \begin{align} x&=&\mathrm{arctanh}\left(cos(\theta)\right)\\y&=&\mathrm{arctanh}\left(cos(\nu)\right)\\z&=&\mathrm{arctanh}\left(\sin\left(\epsilon\right)\right) \end{align}

By solving for $\theta$ in 1 and 2, we see that these are indeed equal:

For the record, incorrect identity

Initially the question was wrongly stated, and the comments below pertain to this: I would like to prove that (1) $$$$\tan\left(\frac{\theta}{2}\right)=\tan\left(\frac{\nu}{2}\right)\tan\left(\frac{\pi/2-\epsilon}{2}\right)$$$$

can transformed to (2) $$x=y+z,$$ where (3) \begin{align} x&=&\mathrm{arctanh}\left(\theta\right)\\y&=&\mathrm{arctanh}\left(\nu\right)\\z&=&\mathrm{arctanh}\left(\sin\left(\epsilon\right)\right) \end{align}

My attempt on incorrect identity:

Taking the tanh of (2) on both sides and using \begin{align} \tanh(x + y) &= \frac{\tanh x +\tanh y}{1+ \tanh x \tanh y } \end{align} results in (2a) $$\boxed{ \theta = \frac{\nu+\sin\left(\epsilon\right)}{1+\nu \sin\left(\epsilon\right)} }$$

On the other hand, using

\begin{align} \tan \frac{\theta}{2} &= \csc \theta - \cot \theta &= \pm\, \sqrt{1 - \cos \theta \over 1 + \cos \theta} &= \frac{\sin \theta}{1 + \cos \theta} &= \frac{1-\cos \theta}{\sin \theta} \end{align}

and $\sin(\pi/2-\epsilon)=\cos(\epsilon)$ and $\cos(\pi/2-\epsilon)=\sin(\epsilon)$ in (1) yields

$$\boxed{ $$\tan\left(\frac{\theta}{2}\right)= \frac{\cos(\epsilon)(1-\cos(\nu))}{\sin(\nu)(1+\sin(\epsilon))}$$ }$$ ... a bit stuck now

• Did you tried starting with tag(y+z) and see if you could derive tag(x) based on the given relation? – Moti Dec 24 '15 at 20:04
• Thank you, but I'm not getting very far. You are saying use tan(arctan) =.... but I dont quite see how this helps now. Otherwise, I know that $\tan(a)\tan(b)=\frac{\cos (A-B)-\cos (A+B)}{\cos (A-B)+\cos (A+B)}$, and that $\operatorname{artanh} \;u \pm \operatorname{artanh} \;v = \operatorname{artanh} \left( \frac{u \pm v}{1 \pm uv} \right)$, but I'm not sure what to follow this up with. – AimForClarity Dec 27 '15 at 7:44
• I have a hard time seeing the connection between tan and arctanh here and why it has come up. – AimForClarity Dec 27 '15 at 7:47
• I am not saying I know the answer - it requires some work. But start with $\tagh(y+z)$ (I made an error in my first comment), this will lead to a relation between the variables under the arc – Moti Dec 27 '15 at 18:34
• Take a look at my attempt, maybe you have some further suggestions – AimForClarity Jan 5 '16 at 2:16

Answer to edited question

We'll begin by squaring your equation $(1)$ and invoking appropriate half-angle formulas:

\begin{align}\tan^2\frac{\theta}{2}= \tan^2\frac{\nu}{2}\tan^2\left(\frac{\pi}{4}-\frac{\epsilon}{2}\right) \qquad\to\qquad \frac{1-\cos\theta}{1+\cos\theta} &= \frac{1-\cos\nu}{1+\cos\nu}\cdot\frac{1-\cos\left(\frac{\pi}{2}-\epsilon\right)}{1+\cos\left(\frac{\pi}{2}-\epsilon\right)} \\[6pt] &= \frac{1-\cos\nu}{1+\cos\nu}\cdot\frac{1-\sin\epsilon}{1+\sin\epsilon} \end{align} Thus, $$(1-\cos\theta)(1+\cos\nu)(1+\sin\epsilon) = (1+\cos\theta)(1-\cos\nu)(1-\sin\epsilon)$$ so that \begin{align} \cos\theta = \frac{\cos\nu + \sin\epsilon}{1+\cos\nu \sin\epsilon} &\quad\to\quad \tanh x = \frac{\tanh y + \tanh z}{1+\tanh y \tanh z}=\tanh(y+z) \\[6pt] &\quad\to\quad x = y+z \quad\square \end{align}

Answer to original question

Why do you think this relation is valid?

• Certainly, if $\epsilon = 0$ (or $z = 0$), then (restricting domains appropriately) $\theta = \nu$ in (1), and $x = y$ in (2), which is consistent.

• But if, say, $\nu = 0$, then (1) reduces to $\tan(\theta/2) = 0$, so that $\theta = 0$ and $x = 0$. However, $\epsilon$ ---and therefore also $z$--- is arbitrary in (1), whereas (2) requires $z = 0$.

Maybe you have some domain restrictions that avoid the second case, and lots of other numerical examples I could post. Let's look more generally.

Solving for $\theta$ in in terms of $\nu$ and $\epsilon$ in two ways, from (1) and (2)+(3), we find ourselves considering this statement: $$2\;\operatorname{atan}\left(\;\tan\frac{\nu}{2}\;\tan\left(\frac{\pi}{4} - \frac{\epsilon}{2}\right) \;\right) \;\stackrel{\text{?}}{=}\; \tanh\left(\;\operatorname{atanh}\nu + \operatorname{atanh} \sin\epsilon\;\right) \tag{\star}$$

Plots of the left- and right-hand sides appear here:

In the image (with $\nu$ and $\epsilon$ bounded by $0$ and $\pi/2$), we see that the plots do match when $\epsilon = 0$ and $\theta = \nu$, as discussed earlier. However, the plots quite clearly pull away from each other, showing a lack of equality for $\epsilon \neq 0$.

Therefore, we "almost-never" satisfy (1) and (2) simultaneously, so that $(\star)$ is not an identity.

• That is true, there is a mistake in the equation that I was given. It doesn't make sense over the domain $\theta \in [0,\pi]$ and $\epsilon \in [0,\pi/2]$ – AimForClarity Jan 7 '16 at 4:36
• I will edit my question above to clarify, I found the right relationship. Now, I have to prove it :) – AimForClarity Jan 7 '16 at 5:14


text:
# 01-08【孟国武】五教5206 吴文俊数学重点实验室数学物理系列报告之2019-19

1. This orbit is diffeomorphic to $\mathrm{SO}_0(2, 2k+2)/\mathrm{U}(1, k+1)$. As a result, it is pre-quantizable.

2. This orbit is the total space of a fiber bundle with base space being the total cotangent space of the punctured euclidean space of dimension $2k+1$ and the fiber being diffeomorphic to $\mathrm{SO}(2n)/\mathrm{U}(n)$. As a result, it admits a canonical polarization.

3. The geometric quantization of this orbit with its canonical polarization yields the Hilbert of square integrable sections of a Hermitian vector bundle over the punctured Euclidean space in dimension $2k+1$; moreover, this Hilbert space provides a geometric realization for the unitary highest weight $\frak{so}(2, 2k+2)$-module with highest weight $(-k-|\mu|, \underbrace{ |\mu|, \ldots, |\mu|}_k, \mu).$

The above results in Lie theory is obtained from the study of magnetized Kepler models in dimension $2k+1$.


text:
Transactions of the IRE Professional Group on Microwave Theory and Techniques

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text:
Poincaré-Bendixson theorem, periodic solutions/periodic orbits

According to my book (Hsu: ODE), a solution $\phi(t)$ to the system $x' = f(x)$ that is bounded for all $t \geq 0$ satisfies one of:

1) $\omega(\phi)$ contains an equilibrium, or

2) either $\phi(t)$ is periodic or $\omega(\phi)$ is a periodic orbit.

My question is: what is the difference between the solution being periodic and the limit set $\omega(\phi)$ being a periodic orbit?

• To me seems consistent. As a limit cycle has a periodic solution (once it attains the limit cycle) and the set of points in the phase space maps a closed orbit. (At least from my physicists point of view). – Chinny84 Jul 29 '15 at 10:48
• A solution spiralling in towards a limit cycle is an example of a non-periodic solution whose omega-limit set (i.e., the limit cycle) is a periodic solution. – Hans Lundmark Jul 29 '15 at 13:46
• Imagine solutions in polar coordinates $(r(t),\theta(t))$ with $\theta(t)=t$ and $r(t)=1-(1-r_0)e^{-t}$, then, for $r_0\ne1$, the solution never meets the unit circle, is not periodic, and has the unit circle as limit set, and the limit set $r=1$ is indeed a periodic orbit. – Did Jul 29 '15 at 13:49
• Oh so an example of a limit set as a periodic orbit is basically a function who tends to a periodic function in the limit? – Benjamin Lindqvist Jul 29 '15 at 17:46

As explained in comments, a non-periodic solution whose limit set is a periodic orbit is something spiraling toward a periodic orbit (either from the inside or from outside). An example of such a system is $$\begin{split} x' &= x\cos(x^2+y^2) - y \\ y' &= y\cos(x^2+y^2)+x\end{split}$$ The plot below (courtesy of Wolfram Alpha) shows two periodic orbits, one of which is attracting (and is the limit set for many non-periodic solutions) and the other one is repelling.


text:
# How do you factor (1/3)(pi)(r^2)(h) + (1/3)(pi)(R^2)(h) ?

Apr 7, 2016

#### Answer:

$\frac{1}{3} \pi h \left({r}^{2} + {R}^{2}\right)$

#### Explanation:

Separate the common factors, $\frac{1}{3} , \pi \mathmr{and} h$ and write the remaining terms, ${r}^{2} \mathmr{and} {R}^{2}$ in the bracket with the correct sign in between.

$= \frac{1}{3} \pi h \left({r}^{2} + {R}^{2}\right)$


text:
Math Help - Solving recursive sequences

1. Solving recursive sequences

So I'm reviewing for an exam, and all the review question put up by the professor is as follows:

Solve.

$r_k = 2*r_{k-1} - r_{k-2}; r_0 = 1, r_1 = 4$

We didn't really cover this in class, and the example in the book is less than adequate, so I"m not sure what to do.

It says that a recurrence relation of the fom

$a_k = A* a_{k-1} + B * a_{k-2}$

Is satisfied by the sequence $1, t, t^2...t^n$ if $t^2 - At - B = 0$

For this problem A = 2 and B = 0, which would make the equation

t^2 - 2t = 0

t(t-2) = 0

So the roots would be t = 0 and t = 2. So the only solution would be the sequence 1, 2, 4, 16... and 1, 0, 0, ...

Is that correct?

2. The sequence $a_k = A* a_{k-1} + B * a_{k-2}$ Is satisfied by the sequence $1, t, t^2...t^n$ if $t^2 - At - B = 0$.

Yes, as can be verified by substitution. But there could be other types of sequences that satisfy the recurrence relation. For example,

3, 6, 12, 24, 48, ...
0, 0, 0, 0, 0, 0, ...

But your sequence 1, 0, 0, 0, ... doesn't satisfy the recurrence relation $a_k=2a_{k-1}$. Do you see why?

- Hollywood

3. Let's write the difference equation as...

$r_{k+2} - 2 r_{k+1} + r_{k} =0$ (1)

It is linear homogenous constant coefficients equation and its solutions is ...

$r_{k} = c_{1}\cdot u_{k} + c_{2}\cdot v_{k}$ (2)

The characteristic equation of (1) is...

$x^{2} - 2\cdot x +1 =0$ (3)

... and it has a single root $x=1$ with multeplicity two. In that case is...

$u_{k} = 1^{k} = 1$

$v_{k} = k\cdot 1^{k} = k$ (4)

... so that...

$r_{k} = c_{1} + c_{2}\cdot k$ (5)

The 'initial conditions' $r_{0}=1$ , $r_{1} = 4$ give $c_{1} = 1$ , $c_{2} = 3$ so that is...

$r_{k} = 1 + 3\cdot k$ (6)

Kind regards

$\chi$ $\sigma$

4. Yes, chisigma's answer is correct. If you set $r_k=1+3k$, then the k=0 and k=1 terms are easily seen to be correct. And substituting in to the recurrence relation gives:

$r_k = 2*r_{k-1} - r_{k-2}$

$1+3k = 2*(1+3(k-1)) - (1+3{k-2})$

$1+3k = 2+6(k-1) - (1+3k-6)$

$1+3k = 2+6k-6 - 1-3k+6=1+3k$, so the recurrence equations are valid.

- Hollywood

5. Hello, Open that Hampster!

Solve: . $r_k \:=\: 2\!\cdot\!r_{k-1} - r_{k-2},\quad r_0 = 1,\;\;r_1 = 4$

I usually crank out the first few terms . . . sometimes there's an obvious pattern.

. . $\begin{array}{ccc}r_0 &=& 1 \\ r_1 &=& 4 \\ r_2 &=& 7 \\ r_3 &=& 10 \\ r_4 &=& 13 \\ & \vdots \end{array}$

This time I lucked out: . $r_n \;=\;3n + 1$


text:
# When Is Angular Momentum Not Conserved: When, Why, How, Detailed Facts And FAQs

Angular momentum is a physical quantity analogous to linear momentum. It is the inherent property of the body or system of particles, which specifies the rotary inertia about an axis (may or may not pass through the body). When external torque acts on the body, the angular momentum is not conserved.

Torque–turning effect of FORCE. Just as in linear kinematics, force is responsible for accelerating or decelerating the body. In the same way, in rotational motion, torque is responsible for rotating the body or system of particles about an axis.

## Principle of Conservation of Angular Momentum

As the principle signifies, if the resultant (net) external torque acting on an object or system of particles is zero. Then the total angular momentum is unchanged or conserved. In other words, the net angular momentum of the system does not change w.r.t time.

The Newton’s second law in angular form can be written as ,

τ=dL/dt

As per the conservation law, for an isolated system , the external torque is zero.

dL/dt=0

Now, it shows,

L = constant

The above principle can also be written as,

the net angular momentum at some time ti = the net angular momentum at some time tf

Li =Lf

So, if the  external torque acts on the body the angular momentum of the body changes. The final momentum and the initial momentum of the system will not be the same.

Lets see an example in which the angular momentum is not conserved.

## What is an example of momentum not being conserved

The body’s angular momentum changes when there is net torque acting on the body, causing an increase or decrease in angular velocity. I.e., Merry-go-round.

Suppose you’re sitting at the center of the merry-go-round, and it was spinning at its axis with some angular speed ω1. After a few minutes, you decided to jump outside of it. Now, According to the conservation of momentum, angular velocity needs to be increased as the moment of inertia (M.O.I depends upon mass and its distribution, and here mass decreases as you jump out of the MGR) decreases.

l1ω1=l2ω2

But, we observe that the angular velocity decreases of the merry-go-round, which evidently shows that the angular momentum is not conserved.

## Question: what is the formula of angular momentum?

There are various formulas of angular momentum.

L=r*p

L=Iω

L=∫τdt

## Question: When is the angular momentum conserved?

When there is no external torque acting on the body or the resultant torque is zero, then it is said to be that the angular momentum is conserved or remains constant of the body or  the system.

## Question: What are the examples of angular momentum being conserved?

Let’s see a few examples related in which it is evidently seen that the angular momentum is being conserved.

• Neutron Star: At the end of life, a massive star’s core can collapse into a tiny and super dense object which is known as a neutron star. Being super dense and diminutive in size, it rotates rapidly. And the rapid rotation exhibits the consequence of the law of conservation of angular momentum. As the star collapses, its moment of inertia decreases (M.O.I– is the product of mass and distance squared), leading to an increase in its angular speed.
• Helicopters have two propellers: Have you wondered why helicopters have two propellers? Is one propeller not enough to move it? Suppose if a helicopter has only one propeller on its head and no external torque acting on it, the angular momentum will remain constant. Initially, the angular momentum is zero as the propeller is not rotating. To conserve angular momentum, The helicopter would start spinning in the opposite direction at its axis as soon as the propeller rotates. Hence, one more propeller is provided on its tail to prevent spinning on its axis.
• Tornado: The inner layer of a tornado, also known as a whirlwind, has high speed as its surface area is less. As no external torque is acting, angular momentum remains unchanged. Due to less surface area, the moment of inertia decreases, making the whirlwind rotate rapidly on its axis.
• Cat landing safely: Well, a cat is very intelligent. It knows how to apply conservation of angular momentum while falling. Whenever a cat falls from heights, it stretches its body and the tail to increase the moment of inertia which ultimately results in a decrease in its speed(as no external torque is acting, so total angular momentum remains unchanged) which makes the cat to land safely.
• A person carrying heavy weight standing on a rotating platform: Suppose, a person is standing on platform by carrying heavy weight in both of his hands. We observe that when his arms are stretched horizontally, his angular velocity is less as soon as he takes his arms closer to its body(it decreases M.O.I), which increases angular velocity.
• Revolution of planets around Sun: The orbits of the planets around the sun are primarily elliptical. As it goes around the sun, its moment of inertia keeps on changing as M.O.I depends upon mass distribution. As they come closer to the sun, the moment of inertia decreases (as distance decreases), and the angular velocity increases (the consequence of conservation of angular momentum).why it happen? Because when the planet is at a far distance, the moment of inertia becomes more so angular velocity decreases as no external torques are acting, angular momentum remains constant.

## Question: What is the moment of inertia?

Moment of inertia is a physical quantity which signifies the mass distribution from its axis of rotation. It is the quantity which is product of mass and square of the distance from its axis.

## Question: What is the dimensional formula of angular momentum and torque?

The dimensional formula of angular momentum is M1L2T-1 and of torque is M1L2T2.